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12 April 2013

Short circuit calculation using MVA method (manual)

By : Gusti  Anggara,
Maaf saya  tulis dalam bahasa inggris, karena ini saya belajar dari literatur berbahasa inggris.

Utility: 150KV, 1000 MVAsc
Transformer 1: 170 MVA, 150/13.8KV, 15% Z

13.8KV Bus
Generator: 100MVA, X"d = 0.2
Transformer 2: 30 MVA, 13.8/6.6KV, 15% Z

6.6KV Bus
Transformer 3: 2MVA, 6.6KV/400V, 10% Z
Motor 1: 10 MVA (Lumped), 20% Z

400V Bus
Motor 2: 1000 KVA (Lumped), 20% Z
Motor 3: 600 KVA (Lumped), 10% Z



In the event of a short circuit, the sources of short circuit current are
1. Utility
2. Generators
3. Motors

 Static loads such as heaters and lighting do not contribute to short circuit.
Transformers and Motors
 Generators
 Cables and Reactors
So, here are the results of MVAsc:
Utility: MVAsc = 1000MVA
Transformer 1: MVAsc = 170 / 0.15 = 1133.33 MVA

13.8KV Bus
Generator: MVAsc = 100 / 0.2 = 500 MVA
Transnformer 2: MVAsc = 30 / 0.15 = 200 MVA

6.6KV Bus
Transformer 3: MVAsc = 2 / 0.1 = 20 MVA
Motor 1: MVAsc = 10 / 0.2 = 50 MVA

400V Bus
Motor 2: MVAsc = 1 / 0.2 = 5 MVA
Motor 3: MVAsc = 0.6 / 0.1 = 6 MVA



Now we calculate the upstream contribution :
At Transformer 1:
MVAsc @ 150KV = 1000 MVA
MVAsc @ 13.8KV = 1/ (1 / 1000 + 1 /1133.33) = 531.25 MVA

At Transformer 2:
MVAsc @ 13.8KV = 531.25 + 500 = 1031.25 MVA
MVAsc @ 6.6KV = 1/ (1 / 1031.25 + 1 / 200) = 167.51 MVA

At Transformer 3:
MVAsc @ 6.6KV = 167.51 + 50 = 217.51 MVA
MVAsc @ 400V = 1/ (1 / 217.51 + 1 / 20) = 18.31 MVA

At 400V Motors
Motor 3: MVAsc = 18.31 x 5 / ( 5 + 6 ) = 8.3 MVA
Motor 4: MVAsc = 18.31 x 6 / ( 5 + 6 ) = 9.98 MVA
The fault MVAsc @bus 400V = 18.31 + 5 + 6 = 29.31MVAsc
The three phase  If = 29.31/(1.732*(0.4)) = 42.3 kA.


Now we come to fault single phase to ground :
For single phase faults, positive sequence, negative sequence and zero sequence
impedances need to be calculated.
If = 3 (I1 + I2 + I0)

Examining the circuit in above, at the 400V Bus, on Transformer 3 contributes to the
zero sequence current.

For transformers, the negative sequence and zero sequence impedance are equal to the positive sequence impedance.

Z1 = Z2 = Z0 or
MVA1 = MVA2 = MVA0
@bus 400V;
1 / MVAsc =1/3 (1 / MVAsc1 + 1 / MVAsc2 + 1 / MVAsc0)
1 / MVAsc = 1/3 (1 / 29.31 + 1 / 29.31 + 1 / 20 )
1/ MVAsc = 

MVAsc = 1/   = 25.4 MVAsc

If= 25.4 / (1.732 x 0.4) = 36.6 kA



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8 komentar:

Hai..Thanks for your sharing..
I have some problem to calculate short circuit on power grid such as PLN's case.
How do we determine MVAsc on power grid base on voltage such as i want calculate short circuit on my plan that connected with PLN which don't know the short circuit. Do you know standard how determine short circuit apparent power?

Thanks

Hi reman,

You can go to the substation that the grid connected in this case your experiment grid and ask for SC value on their busbar.

Regards,

hi anggara,
maaf pakai bhs. indo.
mau nanya nich om, gmn sich cara menentukan nilai arus hubung singkat pada sistem transmisi. apa ad rumus yg bisa digunakan ?
thanks

This comment has been removed by a blog administrator.
This comment has been removed by a blog administrator.

"At 400V Motors
Motor 3: MVAsc = 18.31 x 5 / ( 5 + 6 ) = 8.3 MVA
Motor 4: MVAsc = 18.31 x 6 / ( 5 + 6 ) = 9.98 MVA"

Motor 4 yang mana ya?

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